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11x^2+35x=3000
We move all terms to the left:
11x^2+35x-(3000)=0
a = 11; b = 35; c = -3000;
Δ = b2-4ac
Δ = 352-4·11·(-3000)
Δ = 133225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{133225}=365$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-365}{2*11}=\frac{-400}{22} =-18+2/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+365}{2*11}=\frac{330}{22} =15 $
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